INTRODUCTION
Worldwide, contemporary human civilization is still affected enormously
by its choice of ten as the base of its most frequently used 'decimal'
numeral system in everyday life.
People who are so strongly affected psychosocially that one could call
them "ten-fingered fetishists" even arrange their greatest celebrations
around the number ten, whether it concerns their personal days of birth
and death, historic events decades or hundreds of years ago or less
often occurring millennium festivals.
I hope
i will not need to prove that there is neither a
logical nor a physical connection whatsoever between universal time and
the empirical fact that human beings have almost always two hands with
five fingers each, ten together.
But on top of that it turns out that there is not even a fundamental
connection between these ten fingers and the number we can count up to
by using them in finger counting or 'dactylonomy'!
Quite ironically, time does play a decisive role here in a
different way when we consider the several arithmetic stages
civilization has gone
thru:
- The first stage was that of addition only, a stage without
any awareness of multiplication as an operation in itself.
- The second stage saw the introduction of a systematic repetition
of addition (iterative addition) in what became to be called
"multiplication"
- And in the third stage humankind grew familiar with the
systematic repetition of multiplication (iterative multiplication) in
the shape of raising a number (the base) to another number
(the exponent) in exponentiation.
I will discuss how the maximum numbers which can be reached in each of
these arithmetic stages vary considerably, and show that in the
dactylonomic maximum of our present-day third stage there is nothing
left anymore which favors the decimal-denary system.
(Decimal-denary because a complete numeral system is not supposed
to deal with 'fractions' exclusively, nor with integers exclusively.)
IN THE ERA OF MERE ADDITION
The average 'base-tenner'
never thought about it that with five fingers a human body also
has four spaces between these fingers, and that some fellow humans
once used to base their numeral system on the number of these spaces; or
that a human body does not only normally have ten fingers, but also ten
toes, that is, twenty digits altogether, and that elsewhere this
number was a reason to adopt a base-twenty system instead.
Not only do human bodies normally have all these things, their
fingers, in turn, normally have fourteen clearly distinguishable parts
with their own bones or 'phalanxes' as well: three each on the digits
which anyone will call "fingers" and two on the thumb.
Even if we confine ourselves to addition we have always been able to count
to twelve or fourteen, or up to twenty-four or twenty-eight.
It can be argued that the twelve phalanxes are the (or a) source of the
ancient base-12 numeral system.
However, this 'phalanx counting' differs very much from finger counting in
its limited public visibility and, more importantly, in that you cannot
activate a phalanx in the way you can activate a finger by stretching it.
I will therefore discuss finger counting proper, and only mention phalanx
counting occasionally for comparison.
Whether four- or eight manual interdigital spaces, ten fingers, sixteen
interdigital spaces on hands and feet or twenty digits (or whether twelve
or fourteen phalanxes, whether on one or two hands, or on two hands and
two feet), it is generally taken for granted that with these parts of the
body one cannot count any further than the number of these parts
That conclusion, however, is plainly false, or only true with an
additional assumption of primitivity.
No doubt, primeval finger counting consisted of something like holding
up one hand and using the forefinger of the other to point successively
to each of the digits (thumb or 'fingers' in a narrow sense) on the hand
held up until the number of (thumb and) fingers thus pointed to was the
same as the number of things one had in mind.
If five was not enough, you would just use the fingers of both your
hands to point to and to be pointed to, until ten, the end.
(When counting the phalanxes of your fingers other than your thumbs you
can use your thumb to count their number on the same hand.)
Those were the days of addition and the beginning of number naming, when
an iterative operation such as multiplication was still too abstract to
be comprehended.
People literally did not 'know better' then.
And without multiplication in their tool box, the idea of assigning
different values to their fingers, values different from the elementary
one to ten (or one to twenty-four in phalanx counting), did not emerge,
simply because there was no framework within which to put them.
All you could do after reaching ten was to lay a little twig, stick or
suchlike thing in front of you and return to your first finger, a thumb
or little finger, to start a new round of ten again.
The primeval numeral system simply amounted to a base-one or 'unary'
system, a system which works and suffices for the smallest of integers.
finger counting up to 10
(ten units,
no 'place values' other than 1)
1 1
1_|_1 1_|_1
1___|___1 1___|___1
(1+1+1+1+1)+(1+1+1+1+1)=10
AFTER THE ADVENT OF MULTIPLICATION
But reality was pushing.
Counting beyond ten was possible by remembering the number of ten-finger
rounds, but remembering more and more rounds could not go on
indefinitely.
Two rounds was no problem, because if you even could not remember those,
you still had twenty digits, fingers and toes, on your own body.
The villain of the scene, you may imagine, was the then still unnamed
first number ('twenty-one') after the two rounds or twenty digits.
This number and its successors were part of the third round, and whether
the numbers of the second round had already names or not, people had to
come up with something more systematic, if only to be able to name all
these numbers, since you cannot go on wasting and/or remembering
numerical morphemes forever.
(The very reason why a consistent truly base-60 numeral system is
impossible in practice.)
And yet, the rounds of ten-fingered counting introduced repetition
in arithmetic: the repetition of adding up to ten, a process in which the
first ten was still ten, but the second ten did not refer to just ten
anymore, but to two times ten, the third to three times ten, the fourth
to four times ten, and so on ad infinitum.
Multiplication was born, if not out of necessity, for the sake of
convenience.
Among those who continued to count with their number of left- and
right-hand fingers, and not the spaces between them, and with full
disregard of their toes, the ultra-primitive unary system was replaced
with a more 'civilized' prototype of the base-ten system when the
official counting was not done anymore with fingers in the air, but with
the symbols for numbers carved in bark, clay or stone, written on paper
or another physical medium, including light pixels on a dark background.
With this concretion of counting in the shape of symbols and, later,
whole formulaic expressions, ten-finger counting never got a chance
anymore to prove its incredible numerical power, a power reaching far
beyond the number ten.
Up to today the simple-minded are sure that you cannot count further on
your fingers than ten; that counting further than ten would require
little sticks or suchlike physical means to keep track of the
numerical record.
With our modern notion of numeral systems and the base or 'radix' of a
numeral system, we know that the symbols for numbers, that is figures, in
the denary system are assigned different values dependent on the place of
the figure in the full number notation.
Why couldn't we assign place values to fingers in a similar way?
In primitive ten-finger counting every finger is implicitly assigned the
value 1, but with multiplication having entered our toolbox we could
assign different values to different fingers, albeit without making
explicit use of exponentiation (which is not yet in the toolbox of the
time).
Thus, we could consider a 'base-5' system with multiples of 5, or
a 'base-10' system with multiples of 10, as in the arithmetric sequences
{5,10,15,20,25,30,35,40,45,50} and {10,20,30,40,50,60,70,80,90,100} of
which 5 and 10 are the common differences.
However, this would not make continuous counting possible, if only because
1 to 4 are not covered, or, worse, 1 to 9.
Nonetheless, we have two hands and can split things up:
- the light hand for unit values (among which all single
values needed to fill up the gaps between the multiples)
- the heavy hand for multiplication values (the
multiples of whatever number that serves as a base of
multiplication)
If there are fewer than five unit values, we can, of course, start
with one or more of the lower multiplication values on the light hand.
(Note that in this context i do not apply the terms left and
right to our hands, altho it has the added advantage of doing away
with any skewed connotation these terms may have in some circles.
The reason is that in the communication between people facing one
another there must be agreement, not on what is to be called "right" or
"left" —with my right being your left, and vice versa— but
on what both the sender and the receiver of the numerical message will
have to consider the light and the heavy hand.)
What is most appealing about a multiplication base of 5, is that with
five unit values the values of the light-hand fingers will be 1, 2, 3,
4 and 5, after which the values of the heavy-hand fingers are multiples
of 5: 10, 15, 20, 25 and 30.
The whole light hand will have unit values then, and the whole heavy
hand multiples only.
(I will call the unit values before the base "single (unit) values" or
"singles" for short.)
All numbers between the numbers assigned as place values can be shown
in dactylonomic equations: 6=5+1, 7=5+2, 8=5+3, 9=5+4, 11=10+1, 12=10+2,
13=10+3, 14=10+4, 16=15+1, et cetera.
Above 30 we can make use of equations such as 35=30+5, 40=30+10, 45=30+15,
50=30+20, 55=30+25, 60=30+20+10, 65=30+20+15, 70=30+25+15, 75=30+25+20,
80=30+25+15+10, 85=30+25+15+10+5, 90=30+25+20+15, 95=30+25+20+15+5,
100 = 30+25+20+15+10, 105 = 30+25+20+15+10+5, 110 =
30+25+20+15+10+5+4+1 and 115 = 30+25+20+15+10+5+4+3+2+1.
All addends are arranged in order, descending here, but ascending would
also be possible, depending on where the light and heavy hands are
located.
What is absolutely impossible, however, is to use a place value which
is assigned only once more than once.
For example, after 80=30+25+15+10 you might be inclined to make
85=30+25+15+15, but that would transgress against this rule.
The number 115 is the dactylonomic maximum on this scheme, because,
firstly, it makes use of all place values, without making use of any
place value more than once, and, secondly, because all values between
1 and 115 can also be expressed with the same place values.
Just like we expressed the numbers 6 to 9, so we can express the numbers
31 to 34 as 31=30+1, 32=30+2, 33=30+3, 34=30+4, and 111 to 114 as
111 = 30+25+20+15+10+5+4+2, 112 = 30+25+20+15+10+5+4+3,
113 = 30+25+20+15+10+5+4+3+1 and 114 = 30+25+20+15+10+5+4+3+2.
Whatever you may think of this (not yet perfect) scheme, it is already
a great leap forward from the ancient ten.
finger counting up to 115
(ten different finger place values:
four singles and 5
as the base of five multiples)
3 20
2_|_4 15_||_25
1___|___5 10___||___30
(1+2+3+4+5)+(10+15+20+25+30)=115
At first sight it looks like we could never use a multiplication base of
10, because we would need nine fingers first with the unit values 1 to 9;
and that followed by 10, which would not even leave one finger for the
multiples of 10.
Fortunately, this train of thought is mistaken, because 3=1+2, so we do
not need a 3-valued finger, so long as we have a 4-valued finger; we just
activate the 1-valued pinkie, if that is the one, and the 2-valued
'fourth' finger (counting from the thumb) by stretching them.
(The terms ring finger and annular finger are not
biologically or otherwise acceptable, while it may also be the second
finger, rather than the fourth.)
A 5-, 6-, 7-, or 9-valued finger is likewise not necessary, because their
values can also be expressed by means of two lower-valued fingers or
three lower-valued ones in the case of the number 7=4+2+1.
(Strictly speaking, the 8-valued finger is not absolutely necessary
either, as long as we have a 5-, 6- or 7-valued finger, but the choice of
8 yields the highest maximum.)
So, if we assigned the single values 1, 2, 4, 8 and 10 to the fingers of
the light hand, and the multiples 20, 30, 40, 50 and 60 to the fingers
of the heavy hand, we could count on our ten fingers until
(1+2+4+8+10) + (20+30+40+50+60) = 25+200=225.
This can be shown schematically as:
finger counting up to 225
(four singles and 10
as the base of five multiples)
4 40
2_|_8 30_||_50
1___|___10 20___||___60
(1+2+4+8+10)+(20+30+40+50+60)=225
In the previous scheme we moved from multiples of 5 to multiples of 10,
but it left us with an ugly, if not dirty, light hand in which the
transition of the unit value 8 to the unit value 10 is purely ad hoc.
So, let us return to the beautiful light hand of the earlier scheme, and
completely forget about 10 as a multiplication base.
What should that base be, then, in order to produce a higher maximum?
It follows from the light-hand scheme with place values 1, 2, 3, 4 and 5
that any base will do that does not produce intervals larger than
1+2+3+4+5=15.
By stretching all five fingers of the light hand we can express any
number that is 15 larger than a place value on the heavy hand.
The number 16 cannot be formed anymore in this way (since we can stretch
each finger only once).
Hence, with this light hand, the value 16 should be assigned to the next
finger on the heavy hand, after which the other fingers automatically
receive the values 32, 48, 64 and 80, the multiplication base being 16.
On this scheme the maximum number is 15+(16+32+48+64+80) = 15+240=255
for the two hands together.
As far as the heavy hand is concerned this leaves neither any number
between 0 and 256 that cannot be represented at all nor any number that
can be represented in more than one way.
finger counting up to 255
(five singles and 16
as the base of four multiples)
3 48
2_|_4 32_||_64
1___|___5 16___||___80
(1+2+3+4+5)+(16+32+48+64+80)=255
The light hand is a different matter, because of the superfluity of
first 3 and then 5, which contribute 8 to the maximum, but prevent 96
and 112 from contributing much more — one would say.
This reasoning is erroneous, however: by reducing the number of unit
values to three (1, 2 and 4) their sum will only be 1+2+4=7 and the
distance between multiples on the heavy hand can be no more than 7, so
that the multiplication base cannot be larger than 8.
The result on this purist scheme is therefore (1+2+4+8+16) +
(24+32+40+48+56) = 31+200=231, 24 less than on the last scheme above.
Yet, this is merely the first variant of it, as we may also consider 8
a unit value, so that the distance between multiples may be as large as
1+2+4+8=15, in which case the maximum will be (1+2+4+8+16) +
(32+48+64+80+96) = 31+320=351, 96 more than in the last scheme.
And yet, with our five fingers on the light hand, we may even consider
16 a unit value so that the largest distance allowed between
multiples on this scheme will be 1+2+4+8+16=31.
This means that the first finger on the heavy hand should be given the
value 32.
(The numbers between 16 and 32 will then have the values 17=16+1, 18+16+2,
19=16+2+1, 20=16+4, 21=16+4+1, 22=16+4+2, 23=16+4+2+1, 24=16+8, 25=16+8+1,
26=16+8+2, 27=16+8+2+1, 28=16+8+4, 29=16+8+4+1, 30=16+8+4+2, 31=16+8+4+2+1.)
From now on the last four fingers can be assigned multiples of 32: 64, 96,
128 and 160.
With a multiplication base of 32 we will reach the largest maximum for
a scheme of this type.
Our ten-finger counting will now get us as far as (1+2+4+8+16) +
(32+64+96+128+160) = 31+480=511, 256 more than the last scheme shown above!
finger counting up to 511
(five singles and 32
as the base of four multiples)
4 96
2_|_8 64||128
1___|___16 32__||___160
(1+2+4+8+16)+(32+64+96+128+160)=511
AFTER THE ADVENT OF EXPONENTIATION
In this rather heuristic way we have ascertained that it is possible to
count from 1 up to 511 on our ten fingers without leaving any integer
gap in between; even without any number having more than one
representation in finger language.
This is already an enormously far cry from the days in very ancient times
when people could not count further than ten on their fingers.
In that remote past, we may assume, people never thought about some kind
of place-value system, while —or, rather, precisely because—
multiplication was not known at the time.
Yet, after iterative addition, that is, multiplication, has lifted us up
from 10 (ten) to 511 (five hundred and eleven), nowadays we also have
easy access to iterative multiplication, that is, exponentiation.
Will the maximum number to which we can count on our ten fingers now move
even further to six, seven, eight hundred or more?
And, if so, is there such a number, then, that can be proved to be
the last one, the maximum of dactylonomic maximums?
Radix-ten addicts who are most familiar with ten and the denary
morphemes hundred, thousand and million which follow
in its wake may be delighted now.
For what is more self-evident with a ubiquitous radix of ten and a modern
operation of exponentiation at your disposal than that your ten fingers
should be assigned the place values 1 (10ˆ0), 10 (10ˆ1), 100 (10ˆ2), 1000
(10ˆ3), 10 000 (10ˆ4), 100 000 (10ˆ5), 1 000 000 (10ˆ6), 10 000 000
(10ˆ7), 100 000 000 (10ˆ8) and 1 000 000 000 (10ˆ9)?
Unfortunately, it is far too soon for them to start cheering; for the
same reason that in the era of multiplication, when exponentiation was
still inconceivable, we could not assign the place values 10 (1×10), 20
(2×10), 30 (3×10) up to 100 (10×10), even not the place values 1, 10
(1×10), 20 (2×10) up to 90 (9×10), to our ten fingers.
And whereas the gaps of inexpressible integers left before 10 and between
10 and 20, 20 and 30, et cetera are relatively small in a scheme of
multiples of ten, these gaps grow ever bigger in a scheme of powers of
ten.
For example, you could express the numbers 10, 100 and 110=100+10, or 1,
10 and 11=1+10, but not any of the numbers before 10 or
between 1 and 10; and with the numbers 100 000 000 and 1 000 000
000 you could express numbers such as 100 000 010 or 100 000 001 and 111
111 110 or 111 111 111, but not the great majority of other numbers in
between.
(Don't forget that you can only use a finger once; that you cannot use
your 1-valued finger twice in order to express the number 2, or your
100-valued finger twice in order to express the number 200.)
Perhaps, we should, again, distinguish between unit values on the light
hand, and now powers instead of multiples on the heavy hand.
It should be immediately clear then, that a scheme such as the ones
above with a maximum of 115 and of 255, in which the unit values were
1, 2, 3, 4 and 5 will not be acceptable with powers of 16 and 10
on the heavy hand.
With base 16 it means that 32 (2×16) will be replaced with 256 (16^2),
but the range that can be covered is still 1+2+3+4+5=15, which leaves a
gap of unrepresented integers from 32 to 255 inclusive.
With base 10 it means that 20 will be replaced with 100, but also here
this leaves a gap, albeit a smaller one, from 10+15+1=26 up to 99.
We should, therefore, stick to the light-hand place values of the last
scheme with enabled us to count up to 511; at least insofar as they are
not larger than the base of the powers which follow.
(In this stage we may look at the set {1,2,4,8,16} as lower powers of 2,
altho they were selected because they turned out to be the minimum
number of smallest numbers needed to fill up the gaps on the heavy hand.)
After 16 and 10, let us consider 5 as base of the powers.
The scheme will then start with 1, 2, 4, 5, 25, ...
Since 1+2+4=7 and 5+7=12, it will not be possible to represent 13 to 24,
and we will have to abandon this scheme too.
A scheme with base 4 for the powers will start with 1, 2, 4, 16, ...,
and since 1+2=3 and 4+3=7, it will not be able to represent the numbers
8 to 15, and many other integers to follow later.
A scheme with base 3 for the powers will fare no better or, more
appropriately, it will fare less badly: starting with 1, 2, 3, 9, ...
it will leave the numbers 7 and 8 unaccounted for even before we have
reached 10.
It is not a watertight mathematical proof which i have given here, yet
enough reason not to consider mixed schemes anymore with powers of 2
on the (beginning of the) light hand and powers of 3 or larger on the
heavy hand.
From the moment we recognized multiplication as a presently existing
operation suitable for our purpose we opened the door for the introduction
of finger place values.
However, we cannot but notice that rash applications of the concept of
dactylonomic place values may lead to deplorable drawbacks rather than an
advancement in the search for the largest number in ten-finger counting;
that is, the largest number that does not leave any integer gap on the way!
It is high time i explicitly listed all the conditions that apply in any
search for the largest number that can be reached in finger counting:
- You have ten fingers, and no other things, at your disposal.
(The fact that five of them are on your left, and five on your right
hand, may but does not have to be taken into account.)
- To each finger only one positive integer may be assigned as place
value.
(This does not preclude two or more fingers from having the same place
value.)
- There are only two finger positions: stretched or folded (like on or
off).
In a stretched position a finger or set of fingers is activated, in a
folded position it or they are not.
(Other) gestures do not 'count'.
- Every finger may be activated only once.
(If so, its place value will count; if not, it will not count.)
- The number shown is the sum of the place values of the fingers
stretched or otherwise activated.
(A place value can only occur once in the addition, unless it is
assigned to a number of different fingers not smaller than the number
of times the same place value is added.)
- A number may only be claimed to be the largest that can be shown, if
all integers between 1 and that number, including 1 and the number
itself, can be expressed by means of activating or not activating one or
more of your ten fingers.
(It remains possible that a number can be expressed in more than one way.)
In my last scheme from the era of multiplication, in which the light hand
of units covers precisely, like the heavy hand of multiples, one hand of
fingers, the numbers 1, 2, 4, 8 and 16 were not selected but left
over, because the other numbers in the same range were the sum of two
or three other, smaller numbers.
Nevertheless, it will strike a person familiar with exponentiation
immediately that 1, 2, 4, 8 and 16 are successive integer powers of 2:
2^0, 2^1, 2^2, 2^3 and 2^4.
When looking at each new subrange of integers added to each old range,
the procedure starts with 1 (2^0), after which 2 (2^1) follows, with the
old range containing one integer (1) and the new range two integers, among
which one added integer (2); after 2 the power 4 (2^2) follows,
which adds two integers (3 and 4) to the two previous ones; after 4 the
power 8 (2^3) follows, which adds four integers (5, 6, 7 and 8) to the
four previous ones; and after 8 the power 16 (2^4) follows, which adds
eight integers (9, 10, 11, 12, 13, 14, 15 and 16) to the eight previous
ones, exactly the same number as the number of integers which the old
range contains already.
This pattern is of tremendous importance, because it demonstrates that
every newly added integer between the last, new power and the
previous, old power can be expressed as the sum of that previous power
and one or more smaller powers.
If 2n is the last power and 2m the
second-last (m=n-1), then for any integer x between
these two (2m<x<2n), and
for either ai=0 or ai=1,
it holds that
x=2m×am+2m-1×am-1+2m-2×am-2
... +4×a2+2×a1+a0.
(Altho purely arithmetically also
2n=2m+2m, we
cannot claim this in our finger place value scheme, because by using the
same value twice we are bound to miss out on a higher place value which
could be useful later on.)
When selecting the powers of 2 as place values in finger counting each
added range of integers is of the same length as the range added to.
This unique feature was the underlying reason why we assigned the first
five powers of two to the five fingers on the light hand, and now it
should be the very same reason for assigning the following five powers
of two to the five fingers on the heavy hand.
In other words, to get the largest maximum the total distribution of
place values must be (1+2+4+8+16) + (32+64+128+256+512) = 31+992=1023.
(Note that the numbers 1 to 512 are the powers 2^0 to 2^9, but that the
maximum number we can express this way is 2^10-1=1024-1=1023.)
If my pretty well-founded conjecture above (that all schemes which mix
powers of 2 with other powers such as 3 leave gaps of integers which
cannot be expressed) is accepted as true, 1023 is not just some binary
maximum, but the maximum for any type of ten-finger counting.
finger counting up to 1023
(one single and 2 as the base
of eight larger powers)
4 128
2_|_8 64_|_256
1__|__16 32___|____512
(1+2+4+8+16)+(32+64+128+256+512)=1023
Something definitely remarkable occurred on the path thru time we have
trodden.
We started off with the idea that we could not count any further on our
ten fingers than the number ten, while taking mere addition for granted.
We even shared the common belief that there is an intimate, if not
exclusive, relationship between the human body counting ten fingers and
the historical hegemony of the base-ten numeral system.
Nevertheless we have now arrived at the conclusion that we cannot just
count up to ten on our ten fingers, but up to one thousand and
twenty-three instead.
And that there is a most intimate relationship between this 1023,
not at all with the decimal-denary numeral system, but with the binary
numeral system which is part of a micromacrobinary supersystem.
Those who have six fingers on each hand, that is, twelve together (which
is called "bilateral polydactyly") should even be able to count up to
4095, because 2^12=4096.
POSTSCRIPT
When i wrote the draft for this article i came to the conclusion that
the largest number one could reach in finger counting was 1023.
I considered it my own discovery, because i had never heard or read
about someone arguing the same.
However, between the draft and the final version i decided to have a
closer look at what others might have written about this subject, and
had published on the internet.
That is when i hit upon the Wikipedia article Finger-counting
(at https://en.wikipedia.org/[]wiki/Finger-counting) with a special section
titled "Non-decimal finger-counting".
That section has a two-sentence paragraph about binary finger counting,
called "finger binary", and a four-sentence paragraph about senary finger
counting (which counts up to only 35, but which also explains how to
express sixths and thirty-sixths).
In a special article on the subject, finger binary is defined as
system for counting and displaying binary numbers on [one's]
fingers.
This illustrates very well how my own article above takes an opposite
approach: altho i have in no uncertain terms displayed an aversion to
any exclusive or disproportionate attention paid to the decimal-denary
system, i did not in this article start out from any particular other
numeral system and wanted to know what the maximum was regardless of the
numeral system used.
Displaying binary numbers is not at all the purpose of the present article.
Hence, i decided to publish it, in spite of my not being the
discoverer of the binary number 1111111111 in its capacity as dactylonomic
maximum for the ten-fingered.